The correct option is D 9a2+3a−5
The sum of 4a2+3−7a and 8a−7.
4a2−7a+3
+8a−7
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4a2+a−4
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Now, subtracting (−5a2−2a+1) from (4a2+a−4), we get,
⇒4a2+a−4
−(−5a2−2a+1)
⇒4a2+a−4
+5a2+2a−1
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9a2+3a−5
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