Question 3 (vii)
Subtract:
5a2−7ab+5b2 from 3ab−2a2−2b2
(i) − 5y2 from y2
(ii) 6xy from − 12xy
(iii) (a − b) from (a + b)
(iv) a (b − 5) from b (5 − a)
(v) − m2 + 5mn from 4m2 − 3mn + 8
(vi) − x2 + 10x − 5 from 5x − 10
(vii) 5a2 − 7ab + 5b2 from 3ab − 2a2 −2b2
(viii) 4pq − 5q2 − 3p2 from 5p2 + 3q2 − pq