When term have the same algebraic factors, they are like terms.
Then, we have to subtract the like terms.
When we open the brackets of the second expression, we change the signs of the operator
= 3ab – 2a2 – 2b2 – (5a2 – 7ab + 5b2)
= 3ab – 2a2 – 2b2 – 5a2 + 7ab – 5b2
(1 mark)
= 3ab + 7ab – 2a2 – 5a2 – 2b2 – 5b2
= 10ab – 7a2 – 7b2
(1 mark)