Subtract $6 x + 8 y + 4$ from the sum of $4 x - 2 y + 3$ and $2 y - x + 3$ ?

- x - 8 y - 2

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- 3 x - 8 y + 2

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- 3 x - y + 1

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- x - 8 y + 2

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Solution

The correct option is C $- 3 x - 8 y + 2$
Consider, $(4 x - 2 y + 3) + (2 y - x + 3)$
$= 4 x - 2 y + 3 + 2 y - x + 3$
$= 3 x + 6$
Subtracting $6 x + 8 y + 4$ from $3 x + 6$ we get,
$(3 x + 6) - (6 x + 8 y + 4)$
$= 3 x + 6 - 6 x - 8 y + 4$
$= - 3 x - 8 y + 2$

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