Subtract 6x + 8y + 4 from the sun of 4x $-$ 2y + 3 and 2y $-$ x + 3?

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Solution

$Required polynomial = (4 x - 2 y + 3) + (2 y - x + 3) - (6 x + 8 y + 4) = 4 x - 2 y + 3 + 2 y - x + 3 - 6 x - 8 y - 4 = 4 x - x - 6 x - 2 y + 2 y - 8 y + 3 + 3 - 4 = - 3 x - 8 y + 2$

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Similar questions

6 x + 8 y + 4

4 x - 2 y + 3

2 y - x + 3

Subtract $4 x - 2 y + z$ from the sum of $3 x + 4 y + z$ and $- 6 x + 7 y - 8 z$

(x + y)^{4} = x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + y^{4}

(x - y)^{4} = x^{4} - 4 x^{3} y + 6 x^{2} y^{2} - 4 x y^{3} + y^{4}

(x, y)

4 x - 2 y + 3 = 8

3 x + 6 y = 8 y - x + 5

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