Question

Subtract $7p(3q+7p)$ from $8p(2p-7q)$.

• A. $(33p^2+77pq)$
• B. $(-43p^2-67pq)$
• C. $(43p^2-67pq)$
• D. $(-33p^2-77pq)$

Answer 1

The correct option is D $(-33p^2-77pq)$

Subtract 7p(3q + 7p) from 8p(2p - 7q)
$=8p(2p-7q)-7p(3q+7p)$
$=(8p\times 2p-8p\times 7q)-(7p\times 3q+7p\times 7p)$
$=(16p^2-56pq)-(21pq+49p^2)$
Grouping the like terms together,
$=(16p^2-49p^2)+(-56pq-21pq)$
$=-33p^2-77pq$