Subtract $(8 - 6 x + x^{2} - 7 x^{3} + x^{5})$ from $(x^{4} - 6 x^{3} + x^{2} - 3 x + 1)$ .

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Solution

$\begin{matrix} x^{4} & - 6 x^{3} & + x^{2} & - 3 x & + 1 x^{5} & - 7 x^{3} & + x^{2} & - 6 x & + 8 (-) & (+) & (-) & (+) & (-) - x^{5} + x^{4} & + x^{3} & + 3 x & - 7 \end{matrix}$

$= (- x^{5} + x^{4} + x^{3} + 3 x - 7)$

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Similar questions

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is:

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is

x^{5} - x^{4} + 3^{3} + 4 x^{2} - 3 x - 3

x^{2} + 1

6 x^{3} - 5 x^{2} + 4 x - 2

x + 2 x^{2} - 3 x^{3}

2 - x^{2} + 6 x - x^{3}

x_{1}, x_{2}, x_{3}, x_{4}, x_{5}

\sqrt{x_{1} - 1} + 2 \sqrt{x_{2} - 4} + 3 \sqrt{x_{3} - 9} + 4 \sqrt{x_{4} - 16} + 5 \sqrt{x_{5} - 25} = \frac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5}}{2}

\frac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5}}{2}

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