Subtract( 8−6x+x2−7x3+x5) from( x4−6x3+x2−3x+1).
−x5+x4+x3+3x
−x5+x4+x3−7
−x5+x4+x3+3x−7
−x5+x4+4x3+3x−7
x4−6x3+x2−3x+1 x5−7x3+x2−6x+8(−)(+)(−)(+)(−)−x5+x4+x3+3x−7 =(−x5+x4+x3+3x−7)
x5+x4+x3+x2+x+1 by x3+1
If M is the mean of x1,x2,x3,x4,x5 and x6,prove that (x1−M)+(x2−M)+(x3−M)+(x4−M)+(x5−M)+(x6−M)=0
The degree of the polynomial obtained when 8−6x+x2−7x3+x5 is subtracted from x4−6x3+x2−3x+1 is:
Subtract( 8−6x+x2−7x3+x5) from( x4−6x3+x2−3x+1).