Question

Subtract $8{\mathrm{a}}^3+5{\mathrm{a}}^2+3\mathrm{a}-6$ from $0$

Answer 1

Subtracting $8{\mathrm{a}}^3+5{\mathrm{a}}^2+3\mathrm{a}-6$ from $0$, we get

$0$$-$$8{\mathrm{a}}^3+5{\mathrm{a}}^2+3\mathrm{a}-6$ $=$$-8{\mathrm{a}}^3-5{\mathrm{a}}^2-3\mathrm{a}+6$ $\left[\right(-)\times (-)=+]$ & $\left[\right(+)\times (-)=-]$

Thus,$0$$-$$8{\mathrm{a}}^3+5{\mathrm{a}}^2+3\mathrm{a}-6$ $=-8{\mathrm{a}}^3-5{\mathrm{a}}^2-3\mathrm{a}+6$