Subtract a(2a+b−c)−b(a−2b+2c) from 3c(−2a+3b+c)
(a + b) (2a – 3b + c) – (2a – 3b) c = 2a2 – 2b2 – ab + 4bc – 2ac.
Question 58 (f)
Subtract:
−2a2−2b2 from −a2−b2+2ab.
Question 3 (vii)
5a2−7ab+5b2 from 3ab−2a2−2b2