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Question

Subtract a(2a+bc)b(a2b+2c) from 3c(2a+3b+c)

A
2a22b2+3c25ac+11bc
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B
2a22b2+3c25ac11bc
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C
2a2+2b2+3c25ac+11bc
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D
2a22b2+23c25ac+11bc
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Solution

The correct option is A 2a22b2+3c25ac+11bc
3c(2a+3b+c)[a(2a+bc)b(a2b+2c)]=6ca+9bc+3c2[2a2+abcaba+2b22bc]=2a22b2+3c25ac+11bc

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