Question

Subtract as indicated :
$4\frac{3}{4}-2\frac{1}{6}$

Answer 1

$4\frac{3}{4}-2\frac{1}{6}\Rightarrow \frac{19}{4}-\frac{13}{6}$

Taking L.C.M of $4$ and $6$ we get $12$. So,

$1^{st}$ fraction becomes $\frac{19}{4}=\frac{19\times 3}{4\times 3}=\frac{57}{12}$

$2^{nd}$ fraction becomes $\frac{13}{6}=\frac{13\times 2}{6\times 2}=\frac{26}{12}$

So,

$4\frac{3}{4}-2\frac{1}{6}=\frac{57}{12}-\frac{26}{12}=\frac{57-26}{12}=\frac{31}{12}=2\frac{7}{12}$