Subtract $b (b^{2} + b - 7) + 5$ From $3 b^{2} - 8$ .

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Solution

If we subtract $b (b^{2} + b - 7) + 5$ from $3 b^{2} - 8$ then we get,
$(3 b^{2} - 8) - {b (b^{2} + b - 7)}$
$= 2 b^{2} - b^{3} + 7 b - 8$ .

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