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Question

Subtract:
(i) 5x from 2x
(ii) −xy from 6xy
(iii) 3a from 5b
(iv) −7x from 9y
(v) 10x2 from −7x2
(vi) a2 − b2 from b2 − a2

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Solution

Change the sign of each term of the expression that is to be subtracted and then add.

(i) Term to be subtracted = 5x
Changing the sign of each term of the expression gives -5x.
On adding:

2x+(-5x) = 2x-5x
= (2-5)x
= -3x

(ii) Term to be subtracted = -xy
Changing the sign of each term of the expression gives xy.
On adding:

6xy+xy
= (6+1)xy
= 7xy

(iii) Term to be subtracted = 3a
Changing the sign of each term of the expression gives -3a.
On adding:

5b+(-3a)
= 5b-3a

(iv) Term to be subtracted = -7x
Changing the sign of each term of the expression gives 7x.
On adding:
9y+7x


(v) Term to be subtracted = 10x2
Changing the sign of each term of the expression gives -10x2.
On adding:
−7x2 + (-10x2) = −7x2 −10x2
= (−7−10)x2
= −17x2

(vi) Term to be subtracted = a2 − b2
Changing the sign of each term of the expression gives -a2 + b2.
On adding:
b2 − a2 + (-a2 + b2) = b2 − a2 -a2 + b2
= (1+1)b2 +(−1-1) a2
= 2b2 − 2a2

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