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Byju's Answer
Standard V
Mathematics
Factorising a Given Number to Basic Factors
Subtract 215 ...
Question
Subtract
2
15
from
7
15
A
1
3
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B
9
15
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C
3
5
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Solution
The correct option is
A
1
3
We have to subtract
2
15
from
7
15
⇒
7
15
−
2
15
=
7
−
2
15
=
5
15
Product of prime factors of
5
=
1
×
5
Product of prime factors of
15
=
1
×
5
×
3
∴
5
15
=
1
×
5
1
×
3
×
5
=
1
3
Suggest Corrections
0
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