Question

Subtract$\frac{33}{10}-1\frac{7}{15}$

Answer 1

Find $\frac{33}{10}-1\frac{7}{15}$

First the LCM of $10,15$ is $30$.

$$\begin{gathered} \frac{33}{10}-1\frac{7}{15}=\frac{33}{10}-\frac{22}{15} \\ =\frac{33\times 3}{10\times 3}-\frac{22\times 2}{15\times 2} \\ =\frac{99}{30}-\frac{44}{30} \\ =\frac{99-44}{30} \\ =\frac{55}{30} \\ =\frac{11}{6} \\ \therefore \frac{33}{10}-1\frac{7}{15}=\frac{11}{6} \end{gathered}$$