Subtract 5-7 from 13-7

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Byju's Answer

Standard VI

Mathematics

Subtraction of Fractions

Subtract 5/7 ...

Question

Subtract $\frac{5}{7}$ from $\frac{13}{7}$

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$\frac{6}{7}$

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$\frac{8}{7}$

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$\frac{9}{7}$

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Solution

The correct option is C
$\frac{8}{7}$

The fractions having same denominators are called like fractions.
Numerators are subtracted directly keeping the denominator common for like fractions.
So, $\frac{13}{7} - \frac{5}{7} = \frac{13 - 5}{7} = \frac{8}{7}$

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Similar questions

Subtract :

(i) $\frac{3}{4}$ from $\frac{1}{3}$ (ii) $\frac{- 5}{6}$ from $\frac{1}{3}$ (iii) $\frac{- 8}{9}$ from $\frac{- 3}{5}$

(iv) $\frac{- 9}{7}$ from -1 (v) $\frac{- 18}{11}$ from 1 (vi) $\frac{- 13}{9}$ from 0

(vii) $\frac{- 32}{13}$ from $\frac{- 6}{5}$ (viii) -7 from $\frac{- 4}{7}$

If you subtract $\frac{5}{7}$ from $\frac{13}{7}$ , you will get -

What do we get when we subtract $\frac{5}{7}$ from $\frac{13}{7}$ ?

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$