Question

Subtract :

$\frac{-7}{16}$from $\frac{3}{5}$

Answer 1

Step 1: Make the denominators of both the fractions same

Here denominators of $\frac{-7}{16}$ and $\frac{3}{5}$ are different $(16,5).$

LCM of $(16,5)=80$

Multiply $\frac{-7}{16}by\frac{5}{5}=\frac{-35}{80}$ and

multiply $\frac{3}{5}by\frac{3\times 16}{5\times 16}=\frac{48}{80}$

Step 2: Subtract the fraction of the same denominator

Now, the denominators are equal and We can subtract the numerator values as

$$\begin{gathered} \frac{3}{5}-\frac{-7}{16}=\frac{48}{80}-\frac{-35}{80} \\ =\frac{48-\left(-35\right)}{80} \\ =\frac{48+35}{80} \\ =\frac{83}{80} \end{gathered}$$

Hence, the final answer is $\frac{83}{80}.$