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Question
Subtract:
(i) 4a−7ab+3b+12 from 12a−9ab+5b−3
(ii) 3xy+5yz−7xz from 5xy−2yz−2xz+10xyz
(iii) 4p2q−3pq+5pq2−8p+7q−10 from 18−3p−11q+5pq−2pq2+5p2q
Subtract:
(i) 4a−7ab+3b+12 from 12a−9ab+5b−3
(ii) 3xy+5yz−7xz from 5xy−2yz−2xz+10xyz
(iii) 4p2q−3pq+5pq2−8p+7q−10 from 18−3p−11q+5pq−2pq2+5p2q
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Solution
i)12a−9ab+5b−3−(4a−7ab+3b+12)=12a−9ab+5b−3−4a+7ab−3b−12=12a−4a+5b−3b−9ab+7ab−3−12=8a+2b−2ab−15
ii) 5xy−2yz−2xz+10xyz−(3xy+5yz−7xz)=5xy−2yz−2xz+10xyz−3xy−5yz+7xz=5xy−3xy−2yz−5yz−2xz+7xz+10xyz=2xy−7yz+5xz+10xyz
iii) 18−3p−11q+5pq−2pq2+5p2q−(4p2q−3pq+5pq2−8p+7q−10)
=18−3p−11q+5pq−2pq2+5p2q−4p2q+3pq−5pq2+8p−7q+10
=−3p+8p−11q−7q+5pq+3pq−2pq2−5pq2+5p2q−4p2q+18+10
=5p−18q+8pq−7pq2+p2q+28
i)12a−9ab+5b−3−(4a−7ab+3b+12)=12a−9ab+5b−3−4a+7ab−3b−12=12a−4a+5b−3b−9ab+7ab−3−12=8a+2b−2ab−15
ii) 5xy−2yz−2xz+10xyz−(3xy+5yz−7xz)=5xy−2yz−2xz+10xyz−3xy−5yz+7xz=5xy−3xy−2yz−5yz−2xz+7xz+10xyz=2xy−7yz+5xz+10xyz
iii) 18−3p−11q+5pq−2pq2+5p2q−(4p2q−3pq+5pq2−8p+7q−10)
=18−3p−11q+5pq−2pq2+5p2q−4p2q+3pq−5pq2+8p−7q+10
=−3p+8p−11q−7q+5pq+3pq−2pq2−5pq2+5p2q−4p2q+18+10
=5p−18q+8pq−7pq2+p2q+28
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