Subtract:
(i) $5 x$ from $2 x$
(ii) $- x y$ from $6 x y$
(iii) $3 a$ from $5 b$
(iv) $- 7 x$ from $9 y$
(v) $10 x^{2}$ from $- 7 x^{2}$
(vi) $a^{2} - b^{2}$ from $b^{2} - a^{2}$

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Solution

(i) $2 x - (5 x) = 2 x - 5 x = - 3 x$ [ $∵ - (- a) = + a$ ]
(ii) $6 x y - (- x y) = 6 x y + x y = 7 x y$
(iii) $5 b - 3 a = 5 b - 3 a$
(iv) $9 y - (- 7 x) = 9 y + 7 x$
(v) $- 7 x^{2} - 10 x^{2}$
$= - 17 x^{2}$
(vi) $b^{2} - a^{2} - (a^{2} - b^{2})$
$= b^{2} - a^{2} - a^{2} + b^{2}$
$= 2 b^{2} - 2 a^{2}$

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