Subtract - i-5-8-from-3-8- ii-8-11-from-4-11- iii-4-9-from-5-9- iv-1-4-from-3-8- v-5-8-from-13-16- vi-9-22-from-9-33

(i) 5/8 from 3/8 = 3/8 5/8 = 3×1/8×1 5×1/8×1 = 3 5/8= 8/8= 1 (ii) 8/11 from 4/11 =4/11 ( 8/11 ) =4+8/11=12/11=11/11 (iii) 4/9 from 5/9 = 5/9 4/9 = ...

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Byju's Answer

Standard VII

Mathematics

Subtraction of Rational Numbers

Subtract : i ...

Question

Subtract :
$(i) \frac{5}{8} ~ f r o m \frac{- 3}{8} (i i) \frac{- 8}{11} ~ f r o m \frac{4}{11} (i i i) \frac{4}{9} ~ f r o m \frac{- 5}{9} (i v) \frac{1}{4} ~ f r o m \frac{- 3}{8} (v) \frac{- 5}{8} ~ f r o m \frac{- 13}{16} (v i) \frac{- 9}{22} ~ f r o m \frac{- 9}{33}$

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Solution

$(i) \frac{5}{8} ~ f r o m \frac{- 3}{8} = \frac{- 3}{8} - \frac{5}{8} = \frac{- 3 \times 1}{8 \times 1} - \frac{5 \times 1}{8 \times 1} = \frac{- 3 - 5}{8} = \frac{- 8}{8} = - 1 (i i) \frac{- 8}{11} ~ f r o m \frac{4}{11}$

$= \frac{4}{11} - (\frac{- 8}{11}) = \frac{4 + 8}{11} = \frac{12}{11} = 1 \frac{1}{11} (i i i) \frac{4}{9} ~ f r o m \frac{- 5}{9} = \frac{- 5}{9} - \frac{4}{9} = \frac{- 5 - 4}{9} = \frac{- 9}{9} = - 1 (i v) \frac{1}{4} ~ f r o m \frac{- 3}{8} ∴ LCM of4,8 = 2 \times 2 \times 2 = 8 = \frac{- 3}{8} - \frac{1 \times 2}{4 \times 2} = \frac{- 3 - 2}{8} = \frac{- 5}{8} (v) \frac{- 5}{8} ~ f r o m \frac{- 13}{16}$

$∴ LCM of 8 and 16=16 = \frac{- 13}{16} - (\frac{- 5}{8}) = \frac{- 13 \times 1}{16 \times 1} + \frac{5 \times 2}{8 \times 2} (∵ LCM of 8 and 16=16) = \frac{- 13 + 10}{16} = \frac{- 3}{16} (v i) \frac{- 9}{22} ~ f r o m \frac{- 9}{33}$

$∴ LCM of 22 and 3 = 2 \times 3 \times 11 = 66 = \frac{5}{33} - (\frac{- 9}{22}) = \frac{5 \times 2}{33 \times 2} + \frac{9 \times 2}{22 \times 3} (∵ LCM of 22 and 33=66) = \frac{10 + 27}{660} = \frac{37}{66}$

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Similar questions

Subtract :

(i) $\frac{3}{4}$ from $\frac{1}{3}$ (ii) $\frac{- 5}{6}$ from $\frac{1}{3}$ (iii) $\frac{- 8}{9}$ from $\frac{- 3}{5}$

(iv) $\frac{- 9}{7}$ from -1 (v) $\frac{- 18}{11}$ from 1 (vi) $\frac{- 13}{9}$ from 0

(vii) $\frac{- 32}{13}$ from $\frac{- 6}{5}$ (viii) -7 from $\frac{- 4}{7}$

Subtract the first rational number from the second in each of the following:

(i) $\frac{3}{8}, \frac{5}{8}$

(ii) $\frac{- 7}{9}, \frac{4}{9}$

(iii) $\frac{- 2}{11}, \frac{- 9}{11}$

(iv) $\frac{11}{13}, \frac{- 4}{13}$

(v) $\frac{1}{4}, \frac{- 3}{8}$

(vi) $\frac{- 2}{3}, \frac{5}{6}$

(vii) $\frac{- 6}{7}, \frac{- 13}{14}$

(viii) $\frac{- 8}{33}, \frac{- 7}{22}$

Subtract by using number line:

(1) 6 from 8

(2) 9 from 6

(3) +5 from −7

(4) −4 from +5

(5) −2 from −5

Subtract : 4x – 3z from 9x + 8y + 9z

Q. From the sum of 3x² − 5x + 2 and −5x² − 8x + 9 subtract 4x² − 7x + 9.

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Subtract : (i) 58~from −38(ii) −811~from 411(iii) 49~from −59(iv) 14~from −38(v) −58~from −1316(vi) −922~from −933

Subtract :
$(i) \frac{5}{8} ~ f r o m \frac{- 3}{8} (i i) \frac{- 8}{11} ~ f r o m \frac{4}{11} (i i i) \frac{4}{9} ~ f r o m \frac{- 5}{9} (i v) \frac{1}{4} ~ f r o m \frac{- 3}{8} (v) \frac{- 5}{8} ~ f r o m \frac{- 13}{16} (v i) \frac{- 9}{22} ~ f r o m \frac{- 9}{33}$