Question

Subtract: (In horizontal and in vertical arrangement).

(5) (15x²y² + 3y²z² − 2z²x²) − (2z²y² + 15x²y²)

Answer 1

Horizontal arrangement:
(15x²y² + 3y²z² − 2z²x²) − (2z²y² + 15x²y²)
= 15x²y² + 3y²z² − 2z²x² − 2z²y² − 15x²y²

Combining the like terms, we get:
15x²y² − 15x²y² + 3y²z² − 2y²z² − 2z²x²
= y²z² − 2z²x²

Vertical arrangement:
Writing the like terms one below the other, we get:
$\begin{array}{cccccc}& 15x^2{y}^2& +& 3y^2{z}^2& -& 2z^2{x}^2\\ -& (15x^2{y}^2& +& 2y^2{z}^2)& & \end{array}$

Now, we have:

$\begin{array}{cccccc}& 15x^2{y}^2& +& 3y^2{z}^2& -& 2z^2{x}^2\\ +& -15x^2{y}^2& -& 2y^2{z}^2& & \\ & & & y^2{z}^2& -& 2z^2{x}^2\end{array}$