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Question

Subtract m+6n10 from the sum of 5m+2n25 and 3m+8n15.

A
2m+10n40
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B
m+4n30
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C
2m10n+40
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D
m+4n+30
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Solution

The correct option is B m+4n30
Step 1:––––––
Firstly, we need to add 5m+2n25 and 3m+8n15. This can be done using column method as:


The value of the sum of the algebraic expressions 5m+2n25 and 3m+8n15 is 2m+10n40––––––––––––––.

Step 2–––––:
Now we need to subtract m+6n10 from sum obtained in step 1, 2m+10n40––––––––––––––. This can be done using column method as shown:


The value obtained when m+6n10 is subtracted from 2m+10n40 is m+4n30––––––––––––.

Therefore, option (b.) is the correct answer.

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