Subtract the additive inverse of 56 from the multiplicative inverse of −57×1415.
A
32
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B
−23
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C
−32
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D
23
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Solution
The correct option is B−23 Additiveinverseof56=−56Now−57×1415=−23Multiplicativeinverseof−23=−32nowsubtractingaddtiveinversefrommultiplicativeinverse−32−(−56)=−23