Question

Subtract the algebraic expression: $3a^{2}b-\frac{12ab}{16a^{3}b}$

• A. $\frac{12a^{2}b-3}{4a^2}$
• B. $3\frac{a^{4}b-3}{4a^2}$
• C. $\frac{12a^{4}b-3}{4a^2}$
• D. $\frac{a^{4}b-3}{4a^2}$

Answer 1

The correct option is C $\frac{12a^{4}b-3}{4a^2}$

Given, $3a^{2}b-\frac{12ab}{16a^{3}b}$
$\Rightarrow 3a^{2}b-\frac{3}{4a^2}$
Cross multiplying, we get
$\Rightarrow \frac{12a^{4}b-3}{4a^2}$