Question

Subtract the first rational number from the second in each of the following:
(i) $\frac{3}{8},\frac{5}{8}$

(ii) $\frac{-7}{9},\frac{4}{9}$

(iii) $\frac{-2}{11},\frac{-9}{11}$

(iv) $\frac{11}{13},\frac{-4}{13}$

Answer 1

(i) $\frac{3}{8},\frac{5}{8}$

$=\frac{5}{8}-\frac{3}{8}$

$=\frac{5-3}{8}$

$=\frac{2}{8}$

$=\frac{1}{4}$

(ii) $\frac{-7}{9},\frac{4}{9}$

$=\frac{4}{9}-\frac{(-7)}{9}$

$=\frac{4+7}{9}$

$=\frac{11}{9}$

$=1\frac{2}{9}$

(iii) $\frac{-2}{11},\frac{-9}{11}$

$=\frac{-2}{11}-\frac{(-9)}{11}$\

$=\frac{-2+9}{11}$

$=\frac{7}{11}$

(iv) $\frac{11}{13},\frac{-4}{13}$

$=\frac{11}{13}-\frac{(-4)}{13}$

$=\frac{11+4}{13}$

$=\frac{15}{13}$

$=1\frac{2}{13}$