Question

Subtract the first rational number from the second in each of the following:

(i) $\frac{3}{8},\frac{5}{8}$

(ii) $\frac{-7}{9},\frac{4}{9}$

(iii) $\frac{-2}{11},\frac{-9}{11}$

(iv)$\frac{11}{13},\frac{-4}{13}$

(v) $\frac{1}{4},\frac{-3}{8}$

(vi)$\frac{-2}{3},\frac{5}{6}$

(vii) $\frac{-6}{7},\frac{-13}{14}$

(viii)$\frac{-8}{33},\frac{-7}{22}$

Answer 1

(i) $\frac{3}{8}from\frac{5}{8}=\frac{5}{8}-\frac{3}{8}=\frac{5-3}{8}=\frac{2}{8}=\frac{2÷2}{8÷2}=\frac{1}{4}$

(ii) $\frac{-7}{9}from\frac{4}{9}=\frac{4}{9}-\left(\frac{-7}{9}\right)=\frac{4}{9}+\frac{7}{9}=\frac{4+7}{9}=\frac{11}{9}$

(iii) $\frac{-2}{11}from\frac{-9}{11}=\frac{-9}{11}-\left(\frac{-2}{11}\right)\frac{-9}{11}+\frac{2}{11}=\frac{-9+2}{11}=\frac{-7}{11}$

(iv) $\frac{11}{13}from\frac{-4}{13}=\frac{-4}{13}-\frac{11}{13}=\frac{-4-11}{13}=\frac{-15}{13}$

(v) $\frac{1}{4}from\frac{-3}{8}=\frac{-3}{8}-\left(\frac{1}{4}\right)=\frac{-3}{8}-\frac{1}{4}=\frac{-3-2}{8}(LCM8,4=8)=\frac{-5}{8}$

(vi) $\frac{-2}{3}from\frac{5}{6}=\frac{5}{6}-\left(\frac{-2}{3}\right)=\frac{5}{6}+\frac{2}{3}=\frac{5+4}{6}=\frac{9}{6}=\frac{9÷3}{6÷3}=\frac{3}{2}$

(vii) $\frac{-6}{7}from\frac{-13}{14}=\frac{-13}{14}-\left(\frac{-6}{7}\right)=\frac{-13}{14}+\frac{6}{7}=\frac{-13+12}{14}=\frac{-1}{4}$

(viii) $\frac{-8}{33}from\frac{-7}{22}=\frac{-7}{22}-\left(\frac{-8}{33}\right)=\frac{-21+16}{66}=\frac{-5}{66}$