Subtract the first rational number from the second in each of the following:
(ii) $\frac{- 7}{9}, \frac{4}{9}$

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Solution

To subtract $\frac{- 7}{9}$ from $\frac{4}{9}$

$∴ \frac{4}{9} - (\frac{- 7}{9}) = \frac{4}{9} + \frac{7}{9}$
$= \frac{4 + 7}{9}$
$= \frac{11}{9}$

Hence,the required result is $\frac{11}{9}$

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Similar questions

Subtract the first rational number from the second in each of the following:
(i) $\frac{3}{8}, \frac{5}{8}$

(ii) $\frac{- 7}{9}, \frac{4}{9}$

(iii) $\frac{- 2}{11}, \frac{- 9}{11}$

(iv) $\frac{11}{13}, \frac{- 4}{13}$

Subtract the first rational number from the second in each of the following:

(i) $\frac{3}{8}, \frac{5}{8}$

(ii) $\frac{- 7}{9}, \frac{4}{9}$

(iii) $\frac{- 2}{11}, \frac{- 9}{11}$

(iv) $\frac{11}{13}, \frac{- 4}{13}$

(v) $\frac{1}{4}, \frac{- 3}{8}$

(vi) $\frac{- 2}{3}, \frac{5}{6}$

(vii) $\frac{- 6}{7}, \frac{- 13}{14}$

(viii) $\frac{- 8}{33}, \frac{- 7}{22}$

\frac{- 8}{33}, \frac{- 7}{22}

\frac{1}{4}, \frac{- 3}{8}

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