Subtract the first rational number from the second in each of the following:
(v) $\frac{1}{4}, \frac{- 3}{8}$

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Solution

To subtract $\frac{1}{4}$ from $\frac{- 3}{8}$

$∴ \frac{- 3}{8} - (\frac{1}{4}) = \frac{- 3}{8} - \frac{1 \times 2}{4 \times 2}$
$= \frac{- 3}{8} - \frac{2}{8}$
$= \frac{- 3 - 2}{8}$
$= \frac{- 5}{8}$

Hence,the required result is $\frac{- 5}{8}$

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Similar questions

Subtract the first rational number from the second in each of the following:

(i) $\frac{3}{8}, \frac{5}{8}$

(ii) $\frac{- 7}{9}, \frac{4}{9}$

(iii) $\frac{- 2}{11}, \frac{- 9}{11}$

(iv) $\frac{11}{13}, \frac{- 4}{13}$

(v) $\frac{1}{4}, \frac{- 3}{8}$

(vi) $\frac{- 2}{3}, \frac{5}{6}$

(vii) $\frac{- 6}{7}, \frac{- 13}{14}$

(viii) $\frac{- 8}{33}, \frac{- 7}{22}$

Subtract the first rational number from the second in each of the following:
(i) $\frac{3}{8}, \frac{5}{8}$

(ii) $\frac{- 7}{9}, \frac{4}{9}$

(iii) $\frac{- 2}{11}, \frac{- 9}{11}$

(iv) $\frac{11}{13}, \frac{- 4}{13}$

\frac{3}{8}, \frac{5}{8}

\frac{- 8}{33}, \frac{- 7}{22}

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