Question

Subtract the first rational number from the second in each of the following:​
(vi) $\frac{-2}{3},\frac{5}{6}$

Answer 1

To subtract $\frac{-2}{3}$ from $\frac{5}{6}$

$\therefore \frac{5}{6}-\frac{-2}{3}=\frac{5}{6}+\frac{2}{3}$
$=\frac{5}{6}+\frac{2\times 2}{3\times 2}$
$=\frac{5}{6}+\frac{4}{6}$
$=\frac{5+4}{6}$
$=\frac{9}{6}$
$=\frac{3}{2}$

Hence,the required result is $\frac{3}{2}$