Subtract the polynomial : $x^{5} - 2 x^{2} - 3 x$ from $x^{3} + 3 x^{2} + 1$

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Solution

To subtract the polynomial $x^{5} - 2 x^{2} - 3 x$ from the polynomial $x^{3} + + 3 x^{2} + 1$ , we get
$(x^{3} + + 3 x^{2} + 1) - (x^{5} - 2 x^{2} - 3 x)$
$= - x^{5} + x^{3} + 5 x^{2} + 3 x + 1$

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Similar questions

x^{5} - 2 x^{2} - 3 x

x^{3} + 3 x^{2} + 1

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is:

(i) x^{4} + x^{2} + x - 1; x^{4} - x^{3} - x^{2} + 1

(i i) 5 x^{2} - 2 y + 9; 3 x^{2} + 5 y - 7

- a

q (x) = x^{3} + 2 x^{2} + a

p (x) = x^{5} - x^{4} - 4 x^{3} + 3 x^{2} + 3 x + b ?

What must be subtracted from $x^{3} - 3 x^{2} + 5 x - 1$ to get $x^{3} + 2 x^{2} - 2 x + 11$ ?

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