Question

Subtract the second expression from the first: $\frac{m}{3}+\frac{n}{2};\frac{m}{6}+\frac{n}{4}$

• A. $\frac{m}{5}+\frac{n}{4}$
• B. $\frac{m}{9}+\frac{n}{4}$
• C. $\frac{m}{6}+\frac{n}{4}$
• D. $\frac{m}{2}+\frac{n}{4}$

Answer 1

Answer: (C)

$\frac{m}{6}+\frac{n}{4}$

$(\frac{m}{3}+\frac{n}{2})-(\frac{m}{6}+\frac{n}{4})$
$=\frac{m}{3}+\frac{n}{2}-\frac{m}{6}-\frac{n}{4}$
$=\frac{4m+6n-2m-3n}{12}$
$=\frac{2m+3n}{12}$
$=\frac{2m}{12}+\frac{3n}{12}$
$=\frac{m}{6}+\frac{n}{4}$