Subtract the second expression from the first expression
$3 a^{2} + 8 a b + 2 b^{2}, 3 a^{2} + 4 a b + 6 b^{2}$

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Solution

Given First expression is $3 a^{2} + 8 a b + 2 b^{2}$
Second expression is $3 a^{2} + 4 a b + 6 b^{2}$
Subtracting second expression from first one will give $3 a^{2} + 8 a b + 2 b^{2} - 3 a^{2} - 4 a b - 6 b^{2} = 4 a b - 4 b^{2}$

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