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Question

Subtract the second expression from the first.
(i) (4xy-9z) ; (3xy - 16z) (ii) (5x + 4y + 7z) ; (x + 2y + 3z)
(iii) (14x2 + 8xy + 3y2 ) ; (26x2 - 8xy- 17y2) (iv) (6x2+ 7xy+ 16y2 ) ; (16x2 - 17xy)
(v) (4x + 16z) ; (19y -14z + 16x)

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Solution


(i) (4xy − 9z) − (3xy − 16z)
= 4xy − 9z − 3xy + 16z
= (4xy − 3xy) + (16z − 9z)
= xy + 7z

(ii) (5x + 4y + 7z) − (x + 2y + 3z)
= 5x + 4y + 7z − x − 2y − 3z
= (5x − x) + (4y − 2y) + ( 7z − 3z)
= 4x + 2y + 4z

(iii) (14x2 + 8xy + 3y2) − (26x2 − 8xy − 17y2)
= 14x2 + 8xy + 3y2 − 26x2 + 8xy + 17y2
= (14x2 − 26x2) + (8xy + 8xy) + (3y2 + 17y2)
= −12x2 + 16xy + 20y2

(iv) (6x2+ 7xy+ 16y2 ) − (16x2 - 17xy)
= 6x2 + 7xy + 16y2 − 16x2 +17xy
= (6x2 − 16x2) + (7xy + 17xy) + 16y2
= −10x2 + 24xy + 16y2

(v) (4x + 16z) − (19y − 14z + 16x)
= 4x + 16z − 19y + 14z − 16x
= (4x − 16x) + (16z + 14z) − 19y
= −12x + 30z − 19y

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