Subtract the second expression from the first :
$m^{2} n - 8 + m n^{2}$ and $7 - m^{2} n - m n^{2}$ .

m^{n} + 2 m n^{2} - 14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 m^{2} n + 2 m n^{2} - 15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 m^{2} n + 2 n^{2} - 14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 n^{2} m n + 2 m n^{2} - 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 m^{2} n + 2 m n^{2} - 15$
$m^{2} n - 8 + m n^{2} - (7 - m^{2} n - m n^{2})$
$= m^{2} n - 8 + m n^{2} + m^{2} n - 7 + m n^{2}$
$= 2 m^{2} n + 2 m n^{2} - 15$

Suggest Corrections

Similar questions

-

-

-

-

-

-

-

Identify the reducing agent in the following redox reaction:

$5 S O_{3}^{2 -} + 2 M n O_{4}^{-} + 6 H^{+} \to 5 S O_{4}^{2 -} + 2 M n^{2 +} + 3 H_{2} O$

m^{2} - n^{2}

m + n

m^{3} - n^{3} + m^{2} n - m n^{2}

B i O_{3}^{-} + M n^{2 +} \to B i^{3 +} + M n O_{4}^{-} + H_{2} O

The coefficients of mn in $2 m^{2} n^{2}$ and $2 m^{2} n$ respectively are:

Join BYJU'S Learning Program