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Remainder Theorem

Subtract the ...

Question

Subtract the second polynomial from the first:
$n^{3} - 5 n^{2} + 6; n^{3} - 3 n + 8$

- 5 n^{2} + 3 n - 2

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- 5 + 3 n - 2

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n^{2} + 3 n - 2

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n + 3 n - 2

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Solution

The correct option is A $- 5 n^{2} + 3 n - 2$
$(n^{3} - 5 n^{2} + 6) - (n^{3} - 3 n + 8)$

$= n^{3} - 5 n^{2} + 6 - n^{3} + 3 n - 8$
$= - 5 n^{2} + 3 n - 2$

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lim n \to \infty \frac{1. n + 2 (n - 1) + 3 (n - 2) + . . . . . + n .1}{n^{3}}

2. C_{0} + 5. C_{1} + 8. C_{2} + . . . + (3 n + 2) C_{n} = (3 n + 4) 2^{n - 1}

2 + 5 + 8 + 11 + . . . + (3 n - 1) =

\frac{1}{2}

n (3 n + 1) n

ϵ

n = \frac{3 n}{5} - 1 + \frac{3 n}{5} - 2

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