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Question

Subtract the sum of 23 and 12 from the sum of 56, 712 and 415.

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Solution

Step 1:

Sum of 23 and 12

23+12

=(23×22)+(12×33)

=46+36

=4+36

=76

23+12=76 ---(1)

Step 2:

Sum of 56, 712 and 415

56+712+415

LCM of 6,12 and 15 is 60

=(56×1010)+(712×55)+(415×44)

=5060+3560+1660

=50+35+1660

=10160

56+712+415=10160 ----(2)

Now, lets do (2)-(1)

1016076

=10160(76×1010)

=101607060

=1017060

=3160

Hence, the difference of the sum of 23 and 12from the sum of 56, 712 and 415 is 3160.


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