Subtract the sum of 23 and 12 from the sum of 56, 712 and 415.
Step 1:
Sum of 23 and 12
23+12
=(23×22)+(12×33)
=46+36
=4+36
=76
⇒23+12=76 ---(1)
Step 2:
Sum of 56, 712 and 415
56+712+415
LCM of 6,12 and 15 is 60
=(56×1010)+(712×55)+(415×44)
=5060+3560+1660
=50+35+1660
=10160
⇒56+712+415=10160 ----(2)
Now, lets do (2)-(1)
10160−76
=10160−(76×1010)
=10160−7060
=101−7060
=3160
Hence, the difference of the sum of 23 and 12from the sum of 56, 712 and 415 is 3160.