Subtract the sum of $36 - 4 m - 7 x^{2}$ and $2 t - 3 m - 4 x^{2}$ from the sum of $96 + 2 m - 3 x^{2}$ and $- 36 + m + 4 x^{2}$

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Solution

Sum of 36 -4m -7x^2 & 2t-3m-4x^2, Let y
$y = 36 - 4 m - 7 x^{2} + 2 t - 3 m - 4 x^{2}$
$y = 36 - 7 m + 2 t - 11 x^{2}$ ...(1)

Sum of $96 + 2 m - 3 x^{2}$ & $- 36 + m + 4 x^{2}$ , let z

$z = 96 + 2 m - 3 x^{2} - 36 + m + 4 x^{2}$
$z = 60 + 3 m + x^{2}$ ...(2)

Therefore, $z - y = 60 + 3 m + x^{2} - (36 - 7 m + 2 t - 11 x^{2})$
$= 60 + 3 m + x^{2} - 36 + 7 m - 2 t + 11 x^{2}$
$= 24 + 11 m - 2 t + 12 x^{2}$

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