Question

Subtract the sum of $5\frac{1}{3}$ and $1\frac{7}{12}$ from the sum of $2\frac{5}{3}$and $7$.

Answer 1

Given : fractions are $5\frac{1}{3}$ and $1\frac{7}{12}$ , $2\frac{5}{3}$and 7.

Step 1: Addition of fraction.

$5\frac{1}{3}$ and $1\frac{7}{12}$ it can be written as $\frac{16}{3}and\frac{19}{12}$

Sum of

$$\begin{gathered} \frac{16}{3}+\frac{19}{12} \\ \frac{64+19}{12}=\frac{83}{12} \end{gathered}$$

$2\frac{5}{3}$ it can be written as $\frac{11}{3}$

Sum of $2\frac{5}{3}$ and $7$ will be ..

$$\begin{gathered} \frac{11}{3}+\frac{7}{1} \\ \frac{11+21}{3}=\frac{32}{3} \end{gathered}$$

Step 2: Subtraction of fraction.

Subtraction of the sum of $5\frac{1}{3}$ and $1\frac{7}{12}$ from the sum of $2\frac{5}{3}$and $7$

$$\begin{gathered} \frac{32}{3}-\frac{83}{12} \\ \frac{128-83}{12}=\frac{45}{12}=\frac{15}{4} \end{gathered}$$

Hence, the answer is $\frac{15}{4}=3\frac{3}{4}$