Subtract the sum of $(a + b + c)$ and $(2 a - b + 2 c)$ from $3 a - b + 3 c$ . [3 MARKS]

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Solution

Formulating the equation : 1 Mark
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Result : 1 Mark

According to question

$(3 a - b + 3 c) - [(a + b + c) + (2 a - b + 2 c)]$

$(3 a - b + 3 c) - [(a + b + c + 2 a - b + 2 c)]$

$(3 a - b + 3 c) - (3 a + 3 c)$

$(3 a - b + 3 c - 3 a - 3 c)$

Final answer = - b

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