Subtract the sum of $(a + b + c)$ and $(2 a - b + 2 c)$ from $3 a - b + 3 c$ . Name the type of expression formed. [3 MARKS]

Open in App

Solution

Answer: 1 Mark
Steps: 1 Mark
Type: 1 Mark

According to question,

$(3 a - b + 3 c) - [(a + b + c) + (2 a - b + 2 c)]$

$= (3 a - b + 3 c) - [(a + b + c + 2 a - b + 2 c)]$

$= (3 a - b + 3 c) - (3 a + 3 c)$

$= (3 a - b + 3 c - 3 a - 3 c)$

$= - b$

The given expression contains only $- b$ , So it is a monomial.

Suggest Corrections

Similar questions

Subtract the sum of $(a + b + c)$ and $(2 a - b + 2 c)$ from $3 a - b + 3 c$ . [3 MARKS]

\frac{a}{2} + \frac{b}{3} + \frac{c}{4}

\frac{2 a}{3} + \frac{3 b}{4} + \frac{4 c}{5}

\frac{a}{16} + \frac{b}{12} + \frac{c}{20}

Add $2 a + 3 b + c + d, - a + b - c - d$ and $3 a - 4 b - 2 c - 2 d$ . Find the value of the final expression if a=2, b=3, c=4, d=5. [3 MARKS]

3 a - 2 b + 4 c

- 2 a + b - 5 c

3 a - 2 b + c

2 a^{3} - 3 a^{2} b + 2 a^{2} c

Join BYJU'S Learning Program