Question

Subtract:
$\left(vii\right)2x^2-7xy-y^2$ from $3x^2-5xy+3y^2$

Answer 1

Step: Find the value of $(3x^2-5xy+3y^2)–(2x^2-7xy-y^2)$
We need to subtract $(2x^2-7xy-y^2)$ from $(3x^2-5xy+3y^2)$
$=(3x^2-5xy+3y^2)-(2x^2-7xy-y^2)$
$=3x^2-5xy+3y^2-2x^2+7xy+y^2$
$=3x^2-2x^2-5xy+7xy+3y^2+y^2$
$=x^2+2xy+4y^2$
Hence, the answer is $(x^2+2xy+4y^2).$