Subtracting $2 x^{2} + 6 - 4 x$ from $3 x^{2} - 6 x + 8$ gives .

x^{2} - 2 x + 2

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2 x^{2} - 2 x + 2

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x^{2} - 8 x + 2

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x^{2} + 2 x + 2

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Solution

The correct option is A $x^{2} - 2 x + 2$
Given: $(3 x^{2} - 6 x + 8) - (2 x^{2} + 6 - 4 x)$
Grouping like terms together, we get
$= (3 x^{2} - 2 x^{2}) + (- 6 x + 4 x) + (8 - 6)$
$= x^{2} - 2 x + 2$

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Similar questions

Question 6 (b)

From the sum of $4 + 3 x a n d 5 - 4 x + 2 x^{2}$ , subtract the sum of $3 x^{2} - 5 x a n d - x^{2} + 2 x + 5$ .

2 x^{2} + 6 - 4 x

3 x^{2} - 6 x + 8

Subtract: 2 x^{2} + 6 - 4 x from 3 x^{2} - 6 x + 8.

Subtract: 2 x^{2} + 6 - 4 x from 3 x^{2} - 6 x + 8.

- 3 x^{3} + 4 x^{2} - 5 x + 6

3 x^{3} - 4 x^{2} + 5 x - 6

6 x^{3} - 8 x^{2} + 10 x - 12

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