Subtracting 4m+2n−3p from 5m+3n−3p gives
−m−n
−m−n−p
m+n
m+n+p
(5m+3n−3p)−(4m+2n−3p)
= 5m+3n−3p−4m−2n+3p
= (5m−4m)+(3n−2n)+(−3p+3p)
= m+n
am × an = a______