Subtracting (4m+2n-3p) from (5m+3n-3p) gives
⇒(5m+3n−3p)−(4m+2n−3p) =5m+3n−3p−4m−2n+3p =(5m−4m)+(3n−2n)+(−3p+3p) =m+n
Subtracting 4m+2n−3p from 5m+3n−3p gives