Subtraction of integers is an operation that is

commutative and associative

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not commutative but associative

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neither commutative nor associative

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commutative but not associative.

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Solution

The correct option is C neither commutative nor associative
By property of integers, subtraction of integers is neither associative nor commutative.
Example
$9 - 3 = 6$
$3 - 6 = - 6 \neq (9 - 3)$
$1 - (4 - 8) = 1 - (- 4) = 5$
$(1 - 4) - 8 = - 3 - 8 = - 11$
Hence $(a - b) - c \neq a - (b - c)$

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Similar questions

Q. Subtraction of integers is
(a) commutative but no associative
(b) commutative and associative
(c) associative but not commutative
(d) neither commutative nor associative

Q. Let * be a binary operation on R defined by a * b = ab + 1. Then, * is
(a) commutative but not associative
(b) associative but not commutative
(c) neither commutative nor associative
(d) both commutative and associative

Q. Consider a binary operation * on N defined as a * b = a 3 + b 3 . Choose the correct answer. (A) Is * both associative and commutative? (B) Is * commutative but not associative? (C) Is * associative but not commutative? (D) Is * neither commutative nor associative?

Consider a binary operation $*$ on N defind as $a * b = a^{3} + b^{3}$ . Choose the correct answer.
$(a) *$ both associative and commutative
$(b) *$ commutative but not associative
$(c) *$ is associative but not commutative
$(d) *$ is neither commutative nor associative

Q. Let

*

be a binary operation defined on

R

a * b = \frac{a + b}{4} \forall a, b \in R,

then the operation

*

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Subtraction of integers is an operation that is

The correct option is C neither commutative nor associativeBy property of integers, subtraction of integers is neither associative nor commutative.Example9−3=63−6=−6≠(9−3)1−(4−8)=1−(−4)=5(1−4)−8=−3−8=−11Hence (a−b)−c≠a−(b−c)

The correct option is C neither commutative nor associative
By property of integers, subtraction of integers is neither associative nor commutative.
Example
$9 - 3 = 6$
$3 - 6 = - 6 \neq (9 - 3)$
$1 - (4 - 8) = 1 - (- 4) = 5$
$(1 - 4) - 8 = - 3 - 8 = - 11$
Hence $(a - b) - c \neq a - (b - c)$