Sudha wants to polish a circular table table top of diameter $2.8$ meter.Find the cost of polishing if the rate of polishing of $R s 25$ per square meter.

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Solution

Diameter $= 2.8 m$
Radius $= 1.4 m$
Area of circular table $= π r^{2} = π (1.4) (1.4) = 6.15 ㎡$
Rate of polishing=Rs. $25$
Cost of polishing $= 25 \times 6.15$
$= 153.75$ Rs.

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Similar questions

[use π = 3.14]

Find the cost of a polishing a circular table-top of diameter $1.6 m$ , if the rate of polishing is $R s 15 / m^{2}$ . (Take $π = 3.14$ ).

1.6 m

R s 15 / m^{2}

π = 3.14

R s .15 / m^{2} .

(T a k e π = 3.14)

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