Sudhir's present age is $5$ more than three times of age of Viru. Amit's age is half the age of Sudhir. If the ratio o the sum of Sudhir's and Viru's age to three times Amit's age is $5 : 6$ , then find Viru's age.

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Solution

Let Viru`s age be $x$
Sudhir~s age is $3 x + 5$
Amit`s age is $\frac{3 x + 5}{2}$
Sum of sudhir and Viru`s age $x + 3 x + 5 = 4 x + 5$
Three times Amit`s Age is $\frac{3}{2} (3 x + 5)$
Their ratio is $4 x + 5 : \frac{3}{2} (3 x + 5) = 5 : 6 \frac{8 x + 10}{9 x + 15} = \frac{5}{6} 48 x + 60 = 45 x + 75 3 x = 15 x = 5$

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Sudhir's present age is 5 more than three times of age of Viru. Amit's age is half the age of Sudhir. If the ratio o the sum of Sudhir's and Viru's age to three times Amit's age is 5:6, then find Viru's age.

Let Viru`s age be xSudhir~s age is 3x+5Amit`s age is 3x+52Sum of sudhir and Viru`s age x+3x+5=4x+5Three times Amit`s Age is 32(3x+5)Their ratio is 4x+5:32(3x+5)=5:68x+109x+15=5648x+60=45x+753x=15x=5

Sudhir's present age is $5$ more than three times of age of Viru. Amit's age is half the age of Sudhir. If the ratio o the sum of Sudhir's and Viru's age to three times Amit's age is $5 : 6$ , then find Viru's age.