Question

suggest a way to determine the $\Lambda {}_m^{\circ }$ value of water.

Answer 1

using Kohlraurchs law, which says,

$A^{o}m\left(H_{2}O\right)=A_{m\left(NaOH\right)}^o-A_{m\left(NaCl\right)}^o$

We know the value of $A_m^o$ for $HCl,NaOH$ and $NaCl$ thus by prose calculations, $A_m^o{H}_{2}O$ can be determined