Suggest the suitable solvent for the reaction given below :

H_{2} O

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C_{2} H_{5} O H

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H C O N M e_{2}

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C_{6} H_{6}

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Solution

The correct option is A $H_{2} O$
In the given reaction $B r$ atom is replaced by $O H^{-}$ ion which was made available by $N a O H$ . So a suitable solvent for this reaction should be a polar solvent which would easily give $O H^{-}$ and $H^{+}$ ions.

The next factor should be that the solvent should be aprotic so that neutralization reaction does not occur and $S N_{2}$ substitution reaction takes place easily.

Taking the above two factors in consideration we can conclude that $H C O N M e_{2}$ would be the most suitable solvent for the given reaction.

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C_{2} H_{5} O H + H X \to C_{2} H_{5} X + H_{2} O

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{CH}_{3} COOH + {Na}_{2} {CO}_{3} \to

Column - I	Column - II
a) A nearly ideal solution	p) $H_{2} O + C_{2} H_{5} O H$
b) A solution showing positive deviation	q) $C_{6} H_{6} + C_{6} H_{5} C H_{3}$
c) A solution showing negative deviation	r) $C_{6} H_{6} + C H C l_{3}$
d) An azeotropic mixture	s) $C H_{3} C O C H_{3}$ + $C_{2} H_{5} O H$
	t) $Δ H$ and $Δ V$ are positive
	u) $Δ H$ and $Δ V$ are negative

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