wiz-icon
MyQuestionIcon
MyQuestionIcon
14
You visited us 14 times! Enjoying our articles? Unlock Full Access!
Question

Sukriti has two candles of the same length, one of which burns down in 4 hours, and the other in 7. If she lights both the candles at midnight, then at what point of time would the length of one candle be twice as long as the other?

A
2 hours 18 minutes
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 hour 48 minutes
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 hours 48 minutes
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3 hours 18 minutes
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2 hours 48 minutes
Let the length of the candles be L and the time taken for each candle to become twice as long as the other be T hours.

Taking the candle which burns in 4 hours:

Length burning in 4 hours = L
Length burning in T hours = (TL/4)
So, Length of the candle left to burn = L - (TL/4)

Similarly, for the candle which burns in 7 hours:

Length burning in 7 hours = L
Length burning in T hours = (TL/7)
So, Length of the candle left to burn = L - (TL/7)

Now according the question:
L - (TL/7) = 2 x {L - (TL/4)}
T/2 - T/7 = 1
5T/14 = 1
T = 14/5
= 2 hours 48 minutes

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Completing the Square
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon